**gimpppa.org:**

300 10-pound bags and 120 50-pound bags.

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**Step-by-step explanation:**

To deal with this problem, we need to use Solving linear Systems through multiplying very first method.

We require to produce an equation for each truck that we have.

1st truck deserve to be shown as:

2nd truck deserve to be shown as:

We use 2x since the amount the 2nd truck dead is double the lot of the an initial truck, and also 1/2y because it has fifty percent as countless as the very first truck.

Now the we have actually both our equations, let"s begin by putting them together

Now we can see the we have a portion for our 2nd equation, let"s remove that fraction by multiply the whole equation by 2.

The brand-new equations will be:

Now that we have both equations with entirety numbers we have the right to then proceed to +/- the equations to find a worth of x or y by eliminating one of two people of the two.

Let"s eliminate the y by subtracting both equations to fix for x.

x + y = 9000

-4x+y = 18000

x = 3000

Now that we have actually a worth for x, we deserve to then instead of x from any type of of the two equations.

Let"s use the equation

:y = 6000

Now that we uncovered both worths of x and y, we can then just divide the full values of each from the load of the bags to find how countless of every bag are present in the very first truck.

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x = 3000 (10-pound bags)

3000 / 10 = 300 10-pound bags

y = 6000 (50-pound bags)

6000/50 = 120 50-pound bags

**gimpppa.org:**

First Equation:

**Step-by-step explanation:**

From the offered number line we deserve to see the there space 6 arrows/jumps of equal sizes to with from 0 come

Each small jump is indistinguishable to

. This is since from 0 to there space 2 jumps, for this reason 1 jump will certainly be same to split by 2 i m sorry is same toFrom 0 come

, 6 jumps that are made. In various other words we have the right to say is included to itself 6 time to with to .Adding

6 times to itself also method multiplying by 6. So we can collection up the equation as: