I have tried to understand what the oxidation state because that Mn in $\ceMnO4^-$ is. So far i have understood that O have actually the oxidation state that -2 so due to the fact that there is 4 O the number turns to -8. What wake up to the minus at O? and what is the oxidation state for Mn?


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The sum of the oxidation says of every one of the atoms needs to same the full charge ~ above the ion.

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For example, because that $\ceNH4+$, if every hydrogen atom has an oxidation state the +1, and the all at once charge is +1, climate we have the right to solve because that the oxidation state the nitrogen:

$$\beginaligned 4(+1) + OS_\ceN &= +1\\OS_\ceN &= +1 -4(+1) \\OS_\ceN &= -3\endaligned$$

Similarly, we can do $\ceSO4^2-$. If every oxygen atom has an oxidation state of -2, and the overall charge is -2, we deserve to solve for the oxidation state the sulfur:

$$\beginaligned 4(-2) + OS_\ceS &= -2\\OS_\ceS &= -2 -4(-2) \\OS_\ceS &= +6\endaligned$$


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answered january 6 "19 at 12:28
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Ben NorrisBen Norris
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Seeing together Oxygen has actually an oxidation state of -2 and you have actually 4 Oxygen atoms, the complete charge added by Oxygen = -8. Because the complete charge of this compound = -1, climate in this case Mn = +7+7 - 8 = -1


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answered january 6 "19 in ~ 13:32
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PeteLDWPeteLDW
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As you said Oxygen has the oxidation state of -2 so if we include up all the oxygens they have a -8 oxidation state.

As the oxidation state the the ion is same to its charge, the Mn needs to "balance" the -8 to obtain it as much as -1. Thus the oxidation state that Mn in Mno4- is +7.


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answered jan 6 "19 at 13:33
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LR01LR01
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