I have tried to understand what the oxidation state because that Mn in $\ceMnO4^-$ is. So far i have understood that O have actually the oxidation state that -2 so due to the fact that there is 4 O the number turns to -8. What wake up to the minus at O? and what is the oxidation state for Mn?



The sum of the oxidation says of every one of the atoms needs to same the full charge ~ above the ion.

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For example, because that $\ceNH4+$, if every hydrogen atom has an oxidation state the +1, and the all at once charge is +1, climate we have the right to solve because that the oxidation state the nitrogen:

$$\beginaligned 4(+1) + OS_\ceN &= +1\\OS_\ceN &= +1 -4(+1) \\OS_\ceN &= -3\endaligned$$

Similarly, we can do $\ceSO4^2-$. If every oxygen atom has an oxidation state of -2, and the overall charge is -2, we deserve to solve for the oxidation state the sulfur:

$$\beginaligned 4(-2) + OS_\ceS &= -2\\OS_\ceS &= -2 -4(-2) \\OS_\ceS &= +6\endaligned$$

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answered january 6 "19 at 12:28

Ben NorrisBen Norris
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Seeing together Oxygen has actually an oxidation state of -2 and you have actually 4 Oxygen atoms, the complete charge added by Oxygen = -8. Because the complete charge of this compound = -1, climate in this case Mn = +7+7 - 8 = -1

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answered january 6 "19 in ~ 13:32

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As you said Oxygen has the oxidation state of -2 so if we include up all the oxygens they have a -8 oxidation state.

As the oxidation state the the ion is same to its charge, the Mn needs to "balance" the -8 to obtain it as much as -1. Thus the oxidation state that Mn in Mno4- is +7.

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answered jan 6 "19 at 13:33

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