Most salt in the hard state are electric insulators, because the ions room not mobile (e.g. Salt chloride). However, solid titanium(II) oxide, $\ceTiO (s)$, is a conductor. How is this so?


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The electron configuration of $\ceTi^2+$ is $\mathrm~3d^2~4s^0$.

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$\ceTiO$, like e.g. $\ceFeO$, $\ceCoO$ and also $\ceNiO$, by the absent salt ($\ceNaCl$) structure.

Due come the lower nuclear charge of $\ceTi$ that is 3d orbitals are much less contracted 보다 that of $\ceFe$, $\ceCo$ and also $\ceNi$ which enables for overlapping that the 3d orbitals and the development of a steel d band in $\ceTiO$. The d electron of $\ceTi^2+$ partially fill this band and also lead to electric conductivity. $\ceFeO$, $\ceCoO$ and also $\ceNiO$ on the other hand are electrical insulators.

Note that in this instance it is electrons the act as the mobile charge carriers, not the ions.


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