Carbon tetrabromide also knows as tetrabromomethane is a colorless crystalline solid having the chemistry formula CBr4. It is composed of one carbon followed by 4 bromine atoms. It has a sweet odor and is soluble in ether, chloroform, ethanol, etc. 


In this tutorial, we will comment on carbon tetrabromide(CBr4) lewis structure, molecular geometry, polar or nonpolar, hybridization, bond angle, etc.

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Carbon tetrabromide is toxic by ingestion and uses to make various other chemicals. It is offered as a solvent for greases, waxes, and oils. It has a really high density, so, the is used likewise for separating mineral from assorted impurities.

Properties that Carbon tetrabromide

It has a molar mass of 331.627 g·mol−1.It is insoluble in water.It has a boiling suggest of 189.7 °C and a melting suggest of 94.5 °C.It is denser than water.It has actually a monoclinic tetrahedral structure.
Name that MoleculeCarbon tetrabromide
Chemical formulaCBr4
Molecular geometry the CBr4Tetrahedral
Electron geometry that CBr4Tetrahedral
HybridizationSp³
NatureNonpolar 
Total Valence electron for CBr432

Page Contents show
1 how to draw lewis framework for CBr4?
2 monitor some measures for drawing the lewis dot structure of CBr4
3 What is the molecule geometry the CBr4?
4 What is the Hybridization of CBr4?
5 What is the bond angle of CBr4?
6 Carbon tetrabromide polarity: is CBr4 polar or nonpolar?
7 FAQ
8 an introduction

How to draw lewis framework for CBr4?


CBr4 lewis structure contains carbon atom at middle position whereas 4 bromine atoms neighboring to it. A full of 12 lone pairs and 4 bonded pairs are existing in the lewis structure of CBr4.

The lewis structure of CBr4 is similar to CCl4 and CF4, since, lock all room in the same team in the routine table and also contains the same number of valence electrons.


Follow some measures for illustration the lewis dot structure of CBr4

1. Count total valence electron in CBr4

Finding the total variety of valence electrons in the CBr4 molecule is the very first step for drawing its lewis diagram. “A valence electron is the outermost covering electrons roughly an atom”. To gain the valence electron of one atom, look at its periodic group.

Since we have actually to uncover the valence electron in the CBr4 molecule, so, look in ~ the periodic team of carbon and bromine atoms.

Carbon atoms belong to the 14th periodic team whereas bromine atom are situated in the 17th group, hence, the valence electron because that the carbon atom is 4, and for bromine, it is 7.

⇒ Total number of the valence electron in carbon = 4

⇒ Total variety of the valence electrons in bromine = 7

∴ Total variety of valence electrons obtainable for drawing the lewis framework of CBr4 = 4 + 7(4) = 32 valence electrons  <∴CBr4 molecule has one carbon and four bromine atom>

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2. Discover the least electronegative atom and also placed it at center


As us know, electronegativity increase as we move from left to best in the periodic table. Hence, the bromine atom is an ext electronegative 보다 a carbon atom. Therefore, it deserve to never be placed in a central position due to the fact that it is much less prone come share electrons.

So, place the carbon in the middle position and spread the 4 bromine atom approximately it.

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3. Connect outer atoms to central atom v a solitary bond

Now sign up with each bromine atom come the carbon central atom making use of a solitary bond.

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Now look at the above structure and count the number of valence electrons we used till now. A solitary bond means 2 shared pair electrons. In the above structure, four solitary bonds are provided for connecting each bromine atom come a carbon central atom.


Hence, (4 × 2) = 8 valence electrons are provided from a full of 32 valence electrons that are available for drawing the lewis framework of CBr4.

∴ (32 – 8) = 24 valence electrons

So, we are left with 24 valence electrons more.

4. Location remaining valence electrons beginning from outer atom first

In this step, we have to put the continuing to be valence electron over each external atom to finish their octet first. We know, in the CBr4 molecule, bromine is the external atom, hence, every bromine atom needs 8 electron in its external shell to finish the octet and also attains stability.

So, simply start placing out the continuing to be valence electron approximately each bromine atom till they complete their octet.

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So, by looking at the above structure, we check out each bromine atom it s okay 6 valence electrons represented as dots, and they likewise have 2 valence electron in kind of a solitary bond that is attached to them.


Hence, (6 valence electrons as dots + one solitary bond that has 2 electrons) = 8 valence electrons are present about each bromine atom, hence, they every completed their octet.

5. Complete main atom octet and also make covalent shortcut if necessary

This action is not required at all for make the lewis framework of CBr4 since the carbon main atom currently completed the octet in the 4th step structure as 4 single bonds(that includes 8 electrons) are attached to the carbon atom.

Hence, each atom (carbon and bromine) perfect its octet by having 8 valence electrons roughly them and we additionally used all 32 valence electrons the are easily accessible for illustration the lewis structure of CBr4.

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CBr4 lewis structure

Now us will inspect the security of the CBr4 lewis framework by making use of the formal charge concept.

6. Inspect the stability with the assist of a formal fee concept

“The lesser the formal fee on atoms, the better is the stability of the lewis diagram.”


To calculate the formal fee on one atom. Use the formula provided below-

⇒ official charge = (valence electron – lone pair electron – 1/2 bonded pair electrons)

Let’s start with the main atom i beg your pardon is carbon in the CBr4 molecule.

For carbon atom:

⇒ Valence electrons of carbon = 4

⇒ Lone pair electron on carbon = 0

⇒ common pair electrons roughly carbon(4 single bond) = 8

∴ (4 – 0 – 8/2) = 0 formal charge on the carbon central atom.


Each bromine atom in the CBr4 lewis structure has the same variety of lone pair and bonded pair electrons, hence, just count formal fee for simply one bromine atom

 For bromine atom

⇒ Valence electrons of bromine = 7

⇒ Lone pair electrons on bromine = 6

⇒ common pair electrons about bromine (1 single bond) = 2

∴ (7 – 6 – 2/2) = o formal charge on each bromine atom.

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So, each atom gets the formal charge equal come zero, hence, the above lewis framework of CBr4 is many stable and reliable.


What is the molecular geometry the CBr4?


The molecular geometry that CBr4 is tetrahedral as the carbon main atom has actually no lone pair and also is attached to the four bromine atoms v the aid of a solitary bond. So, over there are four regions that electron density roughly the carbon main atom”.


The electron pair about the carbon central atom will repel every other and also tried come go far from every other, they will take the position where repulsion becomes minimum between them.

According come the VSEPR theory, “in many of the cases, the central atom with 4 regions the density adopt a tetrahedral structure because repulsion is minimum in electron pairs at this position.”

Hence, the last molecular geometry that CBr4 shows up like a continuous tetrahedron through a bond edge ∠Br−C−Br =109.5°.

The carbon atom is situated in the facility of the tetrahedron, when the four bromine atoms are situated on the vertices.

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CBr4 molecular geometry

We can also find the electron and also molecular geometry the CBr4 utilizing the AXN method and VSEPR chart.

AXN is a simple formula that represents the number of the external inspection atom and lone pair ~ above the central atom to predict the shape of the molecule making use of the VSEPR chart.

AXN notation because that CBr4 molecule:

A denotes the main atom, so, carbon is the central atom in CBr4 molecule A = CarbonX denotes the bonded atom to the main atom, carbon is external inspection with 4 bromine atoms. Therefore, X = 4N to represent the lone pair top top the central atom, as per CBr4 lewis structure, the carbon central atom has actually no lone pair. Hence, N = 0

So, the AXN share formula for the CBr4 molecule i do not care AX4N0 or AX4.

As per the VSEPR chart, if a molecule it s okay AX4 generic formula then its molecule geometry will certainly be tetrahedral and electron geometry will also be tetrahedral.


Look at the VSEPR chart below to clear your doubts.

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What is the Hybridization of CBr4?

“Hybridization is a theory that help us understand the form of molecule orbitals upon bonding to for compounds”

We will not go for the deep touch of the hybridization concept, we just want come know how to discover the hybridization the the CBr4 molecule.

Just capture the steric number of the CBr4 molecule to gets it hybridized.

“Steric number is the enhancement of a total number of bonded atoms approximately a main atom and the lone pair existing on it.”

∴ Steric variety of CBr4 = (Number that bonded atoms attached come carbon + Lone pair on carbon atom)

According come the lewis structure of CBr4, the carbon main atom is external inspection with 4 bromine atoms and also it has no lone pairs.

∴ Steric number of CBr4 = (4 + 0) = 4

Steric numberHybridization
1S
2Sp
3Sp²
4Sp³
5Sp³d
6Sp³d²

So, we acquire the Sp3 hybridization because that the CBr4 molecule because the steric number because that the carbon main atom is 4.

What is the bond angle of CBr4?

As we know the molecular geometry of CBr4 is tetrahedral, hence, according to the VSEPR theory, for a tetrahedral structure, the bonded atoms around the central atom will spread out at an edge of approx 109.5° to minimize the repulsion and also attains stability.

Hence, the bond edge of CBr4 is approx 109.5º. 


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A polar molecule has actually an unequal circulation of charges on atoms which results in some net dipole moment, a polar bond usually occurs when the distinction of electronegativity in between the atom is lies between 0.4 to 1.4 according to the Pauling scale.

A nonpolar molecule has actually an equal circulation of fees which outcomes in a zero dipole moment because each dipole created along the bond will certainly cancel out each other, a nonpolar link occurs once the difference of electronegativity in between atoms is less than 0.4 follow to the Pauling scale.

So, Is CBr4 polar or nonpolar? CBr4 is a nonpolar molecule return its bond(C-Br) is polar in nature due to the fact that the difference in electronegativity in between value bromine(2.96) and also carbon(2.55) is 0.41 i beg your pardon lies in the selection of the Pauling scale of electronegativity because that the polar bonds.

It doesn’t median if the bonds of any molecule are polar then the molecule will additionally be polar, the polar or nonpolar counts upon the all at once dipole minute which is a situation of CBr4 molecule is zero due to the fact that of the symmetrical structure that causes the dipole generated along the bond(C-Br) canceled the end each other.

CBr4 is in a tetrahedral molecular shape, so all the dipoles that the 4 polar C-Br bonds cancel each other out, resulting in an in its entirety nonpolar molecule.


FAQ

Why the link of CBr4 is polar but the whole molecule is nonpolar in nature?

The bonds(C-Br) space polar due to the fact that the bromine atom is greater electronegative than the carbon atom, hence, it gets a an adverse charge vice versa, the carbon atom gets a slightly optimistic charge.

Due come the difference in electronegative value in between bromine and carbon, the polarity is generated in the C-Br bond.

But the molecule geometry of CBr4 is tetrahedral i m sorry is symmetrical and all dipoles the C-Br bonds room opposite in direction to each other.

Hence, because of the symmetry of CBr4, all dipole it s okay canceled through each other leaving this molecule v net dipole moment equal come zero which provides it nonpolar in nature.

See more: Is A Trapezoid Is Never A Parallelogram S: Always, Sometimes, Never Flashcards

What room the complete lone pair and bond pairs existing in the CBr4 lewis structure?

There is no lone pair on the carbon central atom but each outer atom(bromine) has 3 lone pairs on it. Hence, (4 bromine atom × 3) = a total of 12 lone pairs.

And there room a total of 4 bonded pairs(single bonds) present in the CBr4 lewis structure