Aluminum reacts through chlorine gas to type aluminum chloride via the complying with reaction:

2Al(s)+3Cl2(g)→2AlCl3(s)2Al(s)+3Cl2(g)→2AlCl3(s)

You are provided 21.0 gg of aluminum and also 26.0 gg of chlorine gas.

You are watching: Aluminum reacts with chlorine gas to form aluminum chloride

Part A: If you had excess chlorine, how countless moles the of aluminum chloride can be produced from 21.0 gg of aluminum?

Express her answer come three far-reaching figures and also include the ideal units.


Part B: If you had actually excess aluminum, how numerous moles that aluminum chloride can be created from 26.0 gg of chlorine gas, Cl2Cl2?
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